Question
Solve the following quadratic equations by factorization:
$\frac{1}{\text{x}-3}+\frac{2}{\text{x}-2}=\frac{8}{\text{x}},$ $\text{x}\neq0, 2, 3$
$\frac{1}{\text{x}-3}+\frac{2}{\text{x}-2}=\frac{8}{\text{x}},$ $\text{x}\neq0, 2, 3$
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