Question
Solve the following system of linear equation graphically and shade the region between the two lines and x-axis:
3x + 2y -11 = 0,
2x - 3y + 10 = 0.
✓
Answer
The system of given equations are,
3x + 2y - 11 = 0 ......(i)
2x - 3y + 10 = 0 ........(ii)
From (i), $\text{y}=\frac{11-3\text{x}}{2}$
Putting x = 1, we get y = 4
Putting x = 3, we get y = 1
Putting x = 5, we get y = -2
Thus, plot A(1, 4), B(3, 1) and C(5, -2) on graph paper.
From (ii), $\text{y}=\frac{2\text{x}+10}{3}$
Putting x = 1, we get y = 4
Putting x = 4, we get y = 6
Putting x = 7, we get y = 8
Thus, plot P(1, 4), Q(4, 6) and R(7, 8) on graph paper.
3x + 2y - 11 = 0 ......(i)
2x - 3y + 10 = 0 ........(ii)
From (i), $\text{y}=\frac{11-3\text{x}}{2}$
Putting x = 1, we get y = 4
Putting x = 3, we get y = 1
Putting x = 5, we get y = -2
Thus, plot A(1, 4), B(3, 1) and C(5, -2) on graph paper.
From (ii), $\text{y}=\frac{2\text{x}+10}{3}$
Putting x = 1, we get y = 4
Putting x = 4, we get y = 6
Putting x = 7, we get y = 8
Thus, plot P(1, 4), Q(4, 6) and R(7, 8) on graph paper.
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