MCQ
$sp^3-$ hybridised nitrogen is present in
- A
- B
- ✓$C{H_2} = CH - \mathop N\limits^ \oplus {H_3}$
- D$C{H_2} = CH - \mathop N\limits^{ \bullet \bullet } {H_2}$
$B) \,sp ^2$ hybridized Nitrogen due to participation of lone pair into ring.
$C) \,CH _2= CH - NH _3+\left( sp ^3\right.$ hybridised nitrogen $)$
$D) \,\left( sp ^2\right.$ hybridised) as nitrogen is in conjugation with double bond. So, option $C)$ is correct.
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$Ag\left( s \right)/A{g^ \oplus }||C{u^{2 + }}/Cu\left( s \right)$
$A{g^ \oplus } + {e^ - } \to Ag\,;\,{E^o} = x$
$C{u^{2 + }} + 2{e^ - } \to Cu\,;\,{E^o} = y$
$E^o_{cell}$ is