Answer


$\begin{array}{l}\sqrt{5} m ^2+\sqrt{5} m +\sqrt{5}=0 \text { compare with } ax ^2+ bx + c =0 \\ \Rightarrow a =\sqrt{5}, b =\sqrt{5} \text { and } c =\sqrt{5} \\ \therefore b ^2-4 ac =\sqrt{5}^2-4(\sqrt{5})(\sqrt{5}) \\ =5-20 \\ =-15 \\ \therefore b ^2-4 ac <0 \text {.hence, roots are not real. }\end{array}$

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