MCQ
Strong reducing behaviour of $H _{3} PO _{2}$ is due to
- ALow oxidation state of $P$
- BPresence of one $-OH$ group and two $P-H$ bonds
- CPresence of two $-OH$ groups and one $P-H$ bonds
- ✓Low coordination number of $P$
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${(C{H_3}O)_2}CHC{H_2}C{H_2}C{H_2}Br\xrightarrow{{Mg}}\xrightarrow{{{H_2}C = O}}\xrightarrow[{heat}]{{{H_3}{O^ + }}}$
(The atomic mass of $Na$ is $23\, g / mol$ ) :