Question
Subtract: $\frac{1}{4} \text { from } \frac{-3}{8}$

Answer

$\frac{1}{4}$ from $\frac{-3}{8}$
$2$ $4, 8$
$2$ $2, 4$
$2$ $1, 2$

 
$1, 1$
$\therefore \text { LCM of } 4,8=2 \times 2 \times 2=8$
$=\frac{-3}{8}-\frac{1}{4}(\therefore \text{LCM}$ of $8$ and $4=8)$
$=\frac{-3 \times 1}{8 \times 1}-\frac{1 \times 2}{4 \times 2}$
$ =\frac{-3-2}{8}=\frac{-5}{8}$

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