^ - 1 1 + ^ - 1 2 + ^ - 1 3 = - Vidyadip

MCQ

${\tan ^{ - 1}}1 + {\tan ^{ - 1}}2 + {\tan ^{ - 1}}3 = $

A
$\frac{\pi }{2}$
B
$\frac{\pi }{4}$
C
$0$
✓
None of these

✓

Answer

Correct option: D.

None of these

d
(d) ${\tan ^{ - 1}}1 + {\tan ^{ - 1}}2 + {\tan ^{ - 1}}3$

$ = {\tan ^{ - 1}}1 + \pi + {\tan ^{ - 1}}\left( {\frac{5}{{ - 5}}} \right)$

$ = {\tan ^{ - 1}}1 + \pi - {\tan ^{ - 1}}1 = \pi $.

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