MCQ
$\tan \left( {{{90}^o} - {{\cot }^{ - 1}}\frac{1}{3}} \right) = $
- A$3$
- B$\frac{2}{3}$
- ✓$\frac{1}{3}$
- D$\frac{1}{{\sqrt {10} }}$
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($A$) $f$ has a local minimum at $x=2$
($B$) fhas a local maximum at $x=2$
($C$) $f^{\prime \prime}(2)>f(2)$
($D$) $f(x)-f^{\prime \prime}(x)=0$ for at least one $x \in \mathbb{R}$
Interval Function