MCQ
$\text{f}(\text{x})=\sqrt{9-\text{x}^2}$. Find the range of the function:
  • A
    $R$
  • B
    $R^{+}$
  • C
    $[-3,3]$
  • $[0,3]$

Answer

Correct option: D.
$[0,3]$
  1. $[0,3]$
Solution:
We know, square root is always non-negative.$\sqrt{9-\text{x}^2}>0$.
So, the range of the function is set of positive real numbers from 0 to 3.

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