MCQ
The alternating current is given by
${i}=\left\{\sqrt{42} \sin \left(\frac{2 \pi}{{T}} {t}\right)+10\right\} {A}$
The $r.m.s.$ value of this current is ${A}$
- ✓$11$
- B$13$
- C$9$
- D$15$
✓
Answer
Correct option: A.
$11$
a
${f}_{{rms}}^{2}={f}_{1 {m} {m}}^{2}+{f}_{2 {rms}}^{2}$
${f}_{{rms}}^{2}={f}_{1 {m} {m}}^{2}+{f}_{2 {rms}}^{2}$
$=\left(\frac{\sqrt{42}}{\sqrt{2}}\right)^{2}+10^{2}$
$=121 \Rightarrow {f}_{{rms}}=11\, {A}$
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