The amplitude of a particle executing $S.H.M.$ with frequency of $60 \,Hz$ is $0.01 \,m$. The maximum value of the acceleration of the particle is
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(a) Maximum acceleration $ = a{\omega ^2} = a \times 4{\pi ^2}{n^2}$
$ = 0.01 \times 4 \times {(\pi )^2} \times {(60)^2} = 144{\pi ^2}\,m/\sec $
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