The angular speed of earth, so that the object on equator may app… - Vidyadip

MCQ

The angular speed of earth, so that the object on equator may appear weightless, is $(g = 10\,m/{s^2}$, radius of earth $6400\, km$)

✓
$1.25 \times {10^{ - 3}}\,rad/sec$
B
$1.56 \times {10^{ - 3}}\,rad/sec$
C
$1.25 \times {10^{ - 1}}\,rad/sec$
D
$1.56\; rad/sec$

✓

Answer

Correct option: A.

$1.25 \times {10^{ - 3}}\,rad/sec$

a
(a) For condition of weightlessness of equator $\omega = \sqrt {\frac{g}{R}} = \frac{1}{{800}} = 1.25 \times {10^{ - 3}}\frac{{rad}}{s}$

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