- AThe distance between the slit and sources
- BWidth of slit
- CWavelength of light
- DFrequency of light
Explanation:
Angular spread of central maxima $=(\theta)=\frac{\lambda}{\text{b}}$
Where $\lambda$ = wavelength of light
b = width of slit
⇒ Clearly, it does depends on the distance between slit and sources.
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(a) |
(b) |
(c) |
(d) |
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(a) |
(b) |
(c) |
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$\text{p}=\text{p}_0\sin(\text{kx}-\omega\text{t})$
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