Download App

Motion in Two Dimension — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsMotion in Two Dimension1 Mark
MCQ
The average acceleration vector for a particle having a uniform circular motion is
  • A
    A constant vector of magnitude $\frac{v^2}{r}$
  • B
    A vector of magnitude $\frac{v^2}{r}$ directed normal to the plane of the given uniform circular motion
  • C
    Equal to the instantaneous acceleration vector at the start of the motion
  • ✓
    A null vector
✓

Answer

Correct option: D.
A null vector
(d) In complete revolution change in velocity becomes zero so average acceleration will be zero.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Motion in Two Dimension→Motion in Two Dimension — all question types→JEE physics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

In the above question, if the internal resistance of the battery is 1 ohm, then what is the reading of ammeter
→
Fundamental frequency of pipe is $100 \mathrm{~Hz}$ and other two frequencies are $300 \mathrm{~Hz}$ and $500 \mathrm{~Hz}$ then
→
Which of the following is not the unit of energy
→
The coil of dynamo is rotating in a magnetic field. The developed induced e.m.f. changes and the number of magnetic lines of force also changes. Which of the following condition is correct
→
A concave lens of focal length $20 \mathrm{~cm}$ placed in contact with a plane mirror acts as a
→
Two springs have their force constant as $k_1$ and $k_2\left(k_1>k_2\right)$. When they are stretched by the same force
→
A double convex lens of focal length $20 \mathrm{~cm}$ is made of glass of refractive index $3 / 2$. When placed completely in water $\left.{ }_a \mu_w=4 / 3\right)$, its focal length will be
→
A train is moving towards north. At one place it turns towards north-east, here we observe that
→
A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after $1.5 s$ and $3.5 s$ respectively, the distance between the cliffs is (Velocity of sound in air $=340 \mathrm{~ms}$ )
→
The equation $\left(P+\frac{a}{V^2}\right)(V-b)$ constant. The units of $a$ are
→