The bob of a simple pendulum of mass m and total energy $E$ will have maximum linear momentum equal to
Easy
Download our app for free and get startedPlay store
(b) ${p_{\max }} = \sqrt {2m\,{E_{\max }}} $
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    The length of simple pendulum is increased by $44\%$. The percentage increase in its time period will be ..... $\%$
    View Solution
  • 2
    The force-deformation equation for a nonlinear spring fixed at one end is $F =4x^{1/ 2}$  , where $F$ is the force (expressed in newtons) applied at the other end and $x$ is the deformation expressed in meters
    View Solution
  • 3
    Two particles are executing S.H.M. The equation of their motion are ${y_1} = 10\sin \left( {\omega \,t + \frac{{\pi T}}{4}} \right),$ ${y_2} = 25\sin \,\left( {\omega \,t + \frac{{\sqrt 3 \pi T}}{4}} \right)$. What is the ratio of their amplitude
    View Solution
  • 4
    A spring is stretched by $5 \,\mathrm{~cm}$ by a force $10 \,\mathrm{~N}$. The time period of the oscillations when a mass of $2 \,\mathrm{~kg}$ is suspended by it is :(in $s$)
    View Solution
  • 5
    What is the maximum acceleration of the particle doing the $SHM$ $y = 2\sin \left[ {\frac{{\pi t}}{2} + \phi } \right]$ where $2$ is in $cm$
    View Solution
  • 6
    The acceleration of a particle in S.H.M. is
    View Solution
  • 7
    A point object is kept in front of a plane mirror. The plane mirror is doing $SHM$ of amplitude $2\,cm$. The plane mirror moves along the $x-$ axis and $x-$ axis is normal to the mirror. The amplitude of the mirror is such that the object is always infront of the mirror. The amplitude of $SHM$ of the image is .... $cm$
    View Solution
  • 8
    A mass $M$ is suspended from a light spring. An additional mass m added displaces the spring further by a distance $x$. Now the combined mass will oscillate on the spring with period
    View Solution
  • 9
    A particle executes linear simple harmonic motion with an ampilitude of $3\,cm$ . When the particle is at $2\,cm$ from the mean position , the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is 
    View Solution
  • 10
    The $S.H.M.$ of a particle is given by the equations $=2 \sin \omega t+4 \cos \omega t$. Its amplitude of oscillation is ........ units
    View Solution