The common region determined by all the constraints of a linear p… - Vidyadip

MCQ

The common region determined by all the constraints of a linear programming problem is called:

A
an unbounded region
B
an optimal region
C
a bounded regio
✓
a feasible region

✓

Answer

Correct option: D.

a feasible region

a feasible region

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If $y = {\left( {x + \sqrt {1 + {x^2}} } \right)^n},$ then $(1 + {x^2}){{{d^2}y} \over {d{x^2}}} + x{{dy} \over {dx}}$ is

If $f(x)=\int_{0}^{x} t \sin t \,d t,$ then $f^{\prime}(x)$ is

The order and degree of the differential equation $y = x\frac{{dy}}{{dx}} + \sqrt {{a^2}{{\left( {\frac{{dy}}{{dx}}} \right)}^2} + {b^2}} $ are

$\int_{}^{} {\frac{{\log x\;dx}}{{{x^3}}} = } $

If $A =\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 2 & 3 \\ 1 & 0 & 1\end{array}\right]$, then $|\operatorname{adj} A |=$ ___________ .

The system of equations $4x + y - 2z = 0\ ,\ x - 2y + z = 0$ ; $x + y - z =0 $ has

The derivative of $f(x) = 3|2 + x|$ at the point ${x_0} = - 3$ is

$\int\limits^\frac{\pi}{3}_\frac{\pi}{6}\frac{1}{\sin2\text{x}}\text{ dx}$ is equal to:

$\log_\text{e}{3}$
$\log_\text{e}\sqrt{3}$
$\frac{1}{2}\log(-1)$
$\log(-1)$

Let A = {x : -1 ≤ x ≤ 1} and f : A → A is a function defined by f(x) = x |x| then f is:

A bijection.
Injection but not surjection.
Surjection but not injection.
Neither injection nor surjection.

Which of the following represents equal vectors:

a, c
b, d
b, c
m, d