- ✓${[Mn{O_4}]^ - }$
- B${[Co{(N{H_3})_6}]^{3 + }}$
- C${[Fe{(CN)_6}]^{3 - }}$
- D${[Cr{({H_2}O)_6}]^{3 + }}$
The electronic configuration of $Mn$ is $[ Ar ] 3 d^{5} 4 s ^{2} .$ In $MnO _{4}^{-}$, oxidation number of $Mn$ is +7 i.e. all
the $3 d$ and $4 s$ electrons are lost to form $\left[M n O_{4}\right]^{-}$ complex. Hence, it has no $d$ -electron.
The electronic configuration of $Mn ( V \|)$ is $[A r] 3 d^{0} 4 s^{0} .$
The complex ions $\left[ Co \left( NH _{3}\right)_{6}\right]^{3+},\left[ Fe ( CN )_{6}\right]^{3-}$ and $\left[ Cr \left( H _{2} O \right)_{6}\right]^{3+}$ have 6, 5 and 3 $d$ -electrons
respectively in the central metal atom.
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$[Figure]$ $\xrightarrow[{S_N2}]{{KOH}}$
Cathode , Anode
This reaction was studied at $-10^{\circ} C$ and the following data was obtained
| run | $[ NO ]_{0}$ | $\left[ Cl _{2}\right]_{0}$ | $r _{0}$ |
| $1$ | $0.10$ | $0.10$ | $0.18$ |
| $2$ | $0.10$ | $0.20$ | $0.35$ |
| $3$ | $0.20$ | $0.20$ | $1.40$ |
$[ NO ]_{0}$ and $\left[ Cl _{2}\right]_{0}$ are the initial concentrations and $r _{0}$ is the initial reaction rate.
The overall order of the reaction is ..........
(Round off to the Nearest Integer).
${C_6}{H_5}Cl + 2NaOH\mathop {\xrightarrow{{200 - {{250}\,^o}C}}}\limits_{200\,atm} {C_6}{H_5}ONa + NaCl + {H_2}O$