MCQ
The complex that has highest crystal field splitting energy $(\Delta )$ is
- A$[Co(NH_3)_5(H_2O)]Cl_3$
- B$K_2[CoCl_4]$
- C$[Co(NH_3)_5Cl]Cl_2$
- ✓$K_3[Co(CN)_6]$
✓
Answer
Correct option: D.
$K_3[Co(CN)_6]$
d
As $CN^-$ is a strong field ligand. $K_3[Co(CN)_6]$ will have maximum $‘\Delta ’.$
As $CN^-$ is a strong field ligand. $K_3[Co(CN)_6]$ will have maximum $‘\Delta ’.$
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$\begin{array}{*{20}{c}}
{\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - C{H_2} - \mathop C\limits^ \oplus {H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array} \to \begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,|} \\
{C{H_3} - \mathop C\limits^ \oplus - CH - C{H_3}} \\
{\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
→{\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - C{H_2} - \mathop C\limits^ \oplus {H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array} \to \begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,|} \\
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