The composition of two simple harmonic motions of equal periods at right angle to each other and with a phase difference of $\pi $ results in the displacement of the particle along
==> ${y_2} = - \frac{{{a_2}}}{{{a_1}}}{y_1}$
This is the equation of straight line.
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Two pendulums differ in lengths by $22\,cm$ . They oscillate at the same place such that one of them makes $15\,oscillations$ and the other makes $18\,oscillations$ during the same time. The lengths (in $cm$ ) of the pendulums are
Time period of a particle executing $SHM$ is $8\, sec.$ At $t = 0$ it is at the mean position. The ratio of the distance covered by the particle in the $1^{st}$ second to the $2^{nd}$ second is :
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