- A$3$ -methyl- $3$ -hexene
- B$4$- chloro- $1$ -methycyclohexane
- ✓$2$ -phenylpentane
- D$1, 3$ -disopropylbenzene
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| $column 1$ | $column 2$ | $column 3$ |
| $(I)$ $1$s orbital | $(i)$ $\psi_{n, l, m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{3}{2}} e^{-\left(\frac{Z r}{a_0}\right)}$ | $image$ |
| ($II$) $2 \mathrm{~s}$ orbital | $(ii)$ One radial node | $(Q)$ Probability density at nucleus $\propto \frac{1}{a_0^3}$ |
| $(III)$ $2 p_z$ orbital | $(iii)$ $\psi_{n, l m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{5}{2}} r e^{-\left(\frac{Z r}{2 a_0}\right)} \cos \theta$ | $(R)$ Probability density is maximum at nucleus |
| $(IV)$ $3 \mathrm{~d}_{\mathrm{z}}^2$ orbital | $(iv)$ $x y$-plane is a nodal plane | $(S)$ Energy needed to excite electron from $n=2$ state to $n=4$ state is $\frac{27}{32}$ times the energy needed to excite electron from $n=2$ state to $n=6$ state |
($1$) For the given orbital in Column $1$, the only $CORRECT$ combination for any hydrogen-like species is
$[A] (IV) (iv) (R)$ $[B] (II) (ii) (P)$ $[C] (III) (iii) (P)$ $[D] (I) (ii) (S)$
($2$) For $\mathrm{He}^{+}$ion, the only INCORRECT combination is
$[A] (II) (ii) (Q)$ $[B] (I) (i) (S)$ $[C] (I) (i) (R)$ $[D] (I) (iii) (R)$
($3$) For hydrogen atom, the only $CORRECT$ combination is
$[A] (I) (iv) (R)$ $[B] (I) (i) (P)$ $[C] (II) (i) (Q)$ $[D] (I) (i) (S)$
Give the answer quetion ($1$) ($2$) and ($3$)
| List $I$ (Spectral Series for Hyddrogen) | List $II$ (Spectral Region/Higher Energy State) |
| $A$. Lyman | $I$. Infrared region |
| $B$. Balmer | $II$. $UV$ region |
| $C$. Paschen | $III$. Infrared region |
| $D$. Pfund | $IV$. Visible region |
Choose the correct answer from the options given below :-
$(A)$ $O$ - $O$ bond lengths are equal.
$(B)$ Thermal decomposition of $O _3$ is endothermic.
$(C)$ $O _3$ is diamagnetic in nature.
$(D)$ $O _3$ has a bent structure.