MCQ
The compound which shows metamerism is :
- A$\mathrm{C}_{5} \mathrm{H}_{12}$
- B$\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}$
- C$\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}$
- ✓$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
✓
Answer
Correct option: D.
$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
d
$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
$\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
This molecular formula is applicable for homologous series ether (-O-) a bivalent functional group and as we know ether with minimum four-C shows metamerism. $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\, \&\, \mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ are metamers.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Major product $(Q)$ of following reaction is used to form :
→Insulin is a protein which plays the role of
$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C{H_3}\,\,} \\
|\,\,\,
\end{array}\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,C{H_3}\,\,\,\,}
\end{array}$ $\xrightarrow[{(cold)}]{{HI}}$ Product is
→{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C{H_3}\,\,} \\
|\,\,\,
\end{array}\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,C{H_3}\,\,\,\,}
\end{array}$ $\xrightarrow[{(cold)}]{{HI}}$ Product is
The $NaNO _{3}$ weighed out to make $50\, mL$ of an aqueous solution containing $70.0 \,mg \,Na ^{+}$ per $mL$ is $...... \,g$.
→(Rounded off to the nearest integer) [Given : Atomic weight in $g\, mol ^{-1}- Na : 23$; $N : 14 ; O : 16]$
Major product obtained by dehydration of given alcohol is
Correct increasing order for the wave lengths of absorption in the visible region for the complexes of $Co^{3+}$ is
→Which of the following statements is correct for the spontaneous adsorption of a gas?
$1^o$ amine and $2^o$ Amine can be differentiated by
→Which one has $pH$ $12$
→Consider the following reaction,
→$2 H _2( g )+2 NO ( g ) \rightarrow N _2( g )+2 H _2 O ( g )$
which following the mechanism given below:
$2 NO ( g ) \underset{ k _{-1}}{\stackrel{ k _1}{\rightleftharpoons}} N _2 O _2( g )$
$N _2 O _2( g )+ H _2( g ) \stackrel{ k _2}{\rightleftharpoons} N _2 O ( g )+ H _2 O ( g )$
$N _2 O ( g )+ H _2( g ) \stackrel{ k _3}{\rightleftharpoons} N _2( g )+ H _2 O ( g )$
(fast equilibrium)
(slow reaction)
(fast reaction)
The order of the reaction is