MCQ
The condition for a stable wave is
- A$n\lambda = 6\prod r$
- B$n\lambda = \frac{1}{2}\prod r$
- ✓$n\lambda = 8\prod r$
- D$n\lambda = 4\prod r$
✓
Answer
Correct option: C.
$n\lambda = 8\prod r$
c
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which carbocation is the most stable ?
The hybridisation present in ${C_2}{H_2}$ is
→The incorrect order of $1^{st}$ $IP$ of the elements is
→Which pair of ion is colourless
Ethyl alcohol is industrially prepared from ethylene by
Magnetic moment of the complexes is zero in
How many secondary amine are possible with molecular formula $C_4H_{11}NH_2$
→Following is a confirmatory test for aromatic primary amines. Identify reagent $(A)$ and $(B)$
→The successive ionisation energy values for an element $X$ are given below element $X$ belongs to group :-
$A. 1^{st}$ ionisation energy $= 410\, kJ\, mol^{-1}$
$B. 2^{nd}$ ionisation energy $= 820\, kJ\, mol^{-1}$
$C. 3^{rd}$ ionisation energy $= 1100\, kJ\, mol^{-1}$
$D. 4^{th}$ ionisation energy $= 1500\, kJ\, mol^{-1}$
$E. 5^{th}$ ionisation energy $= 3200\, kJ\, mol^{-1}$
→$A. 1^{st}$ ionisation energy $= 410\, kJ\, mol^{-1}$
$B. 2^{nd}$ ionisation energy $= 820\, kJ\, mol^{-1}$
$C. 3^{rd}$ ionisation energy $= 1100\, kJ\, mol^{-1}$
$D. 4^{th}$ ionisation energy $= 1500\, kJ\, mol^{-1}$
$E. 5^{th}$ ionisation energy $= 3200\, kJ\, mol^{-1}$
For the complexes showing the square pyramidal structure, the $d-$ orbital involved in the hybridisation is
→