($ii$) due to scandide contraction Ga has more $I.E$. as compared to $\mathrm{A} \ell$
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Statement $(I)$ : The oxidation state of an element in a particular compound is the charge acquired by its atom on the basis of electron gain enthalpy consideration from other atoms in the molecule.
Statement $(II)$ : $\mathrm{p} \pi-\mathrm{p} \pi$ bond formation is more prevalent in second period elements over other periods.
In the light of the above statements, choose the most appropriate answer from the options given below :

$(a)$ Ionisation energy $(Na < Li < B < Be)$
$(b)$ Electron affinity $(N < P < O < S)$
$(c)$ Electron negativity $(S < O < Cl < F)$
$(d)$ Atomic radii $(F < N < O < Na)$