MCQ
The correct representation of CuSO4⋅5H2O is:
- A[Cu(H2O)5]SO4
- B[Cu(H2O)3SO4]⋅2H2O
- C[CuSO4⋅H2O]⋅4H2O
- D[Cu(H2O)4]SO4⋅H2O
Explanation:
For,
CuSO4.5H2O in this 4H2O are bonded by co-ordinate bond and 1H2O by covalent bonding.
Therefore,
Its formula of the compound is [Cu(H2O)4]SO4⋅H2O.
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$E_{\frac{1}{2}Cl_2/Cl^- }^o = 1.36\,V\,,\,E_{C{r^{3 + }}/Cr}^o = - 0.74\,V$
$E_{C{r_2}O_7^{2 - }/C{r^{3 + }}}^o = 1.33\,V\,,\,E_{MnO_4^ - /M{n^{2 + }}}^o = 1.51\,V$
The correct order of reducing power of the species $(Cr, Cr^{3+}, Mn^{2+}$ and $Cl^-)$ will be
$HC \equiv CH\mathop {\xrightarrow{{{\text{1% HgS}}{{\text{O}}_{\text{4}}}}}}\limits_{20\% {H_2}S{O_4}} A\xrightarrow{{C{H_3}MgX}}B\xrightarrow{{[O]}}$


$A$ is