MCQ
The correct sequence of elements in decreasing order of first ionisation energy is
- A$Na > Mg > Al$
- B$Mg > Na > Al$
- C$Al > Mg > Na$
- ✓$Mg > Al > Na$
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(Given : $\Delta_{\mathrm{r}} \mathrm{H}_{298 \mathrm{~K}}^{\circ}=-54.07 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta_{\mathrm{I}} \mathrm{S}_{298 \mathrm{~K}}^{\circ}=10 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ and $\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} ; 2.303 \times 8.314 \times 298=5705$ )
$kJ\,mol ^{-1}$ (Nearest integer)
Given : $\Delta_{ dis } H _{ Cl _{2(g)}}^{\circ}=240\,kJ\,mol ^{-1}$.
$\Delta_{ eg } H _{ Cl _{(g)}}^{\circ}=-350\,kJ\,mol ^{-1}$,
$\Delta_{ hyd } H _{ Cl i _{( j )}^{\circ}}^{\circ}=-380\,kJ\,mol ^{-1}$