- Atwo $p \pi - d \pi$ bond
- Bmolecule bas $2$ lone pair, $2 \sigma$ bonds and $2 \pi$ bonds
- Ctwo $p \pi - p \pi$ bonds
- ✓one $p \pi - p \pi$ and one $p \pi - d \pi$ bond
$\mathrm{SO}_{2}=6+6(2)=18 \mathrm{e}-16 \mathrm{e}=2 \mathrm{e} \rightarrow 1$ lone pair
$\rightarrow \mathrm{G} . \mathrm{S}=[\mathrm{Ne}] 3 \mathrm{s}^{2} 3 \mathrm{p}^{4}$
2 Unpaired electron $1^{\text {st }}$ E.S. $=[\mathrm{Ne}] 3 \mathrm{s}^{2} 3 \mathrm{p}^{3} 3 \mathrm{d}^{1}$
4 unpaired electron $\mathrm{O} \rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{4}$
$\rightarrow$ Geometry of $\mathrm{SO}_{2}$ is BENT/ANGULAR
$\rightarrow$ one $\mathrm{p} \pi-\mathrm{p} \pi$ and one $\mathrm{p} \pi-\mathrm{d} \pi$ Bond
$\rightarrow 2 \pi$ Bonds
$\rightarrow 1$ lone pair on the central atom.
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| Element | Atomic mass |
| $A$ | $12.01$ |
| $B$ | $35.5$ |
$A$ and $B$ combine to form new substance $X$ . If $4\,moles$ of $B$ combine with $1\,mole$ of $A$ to give $1\,mole$ of $X,$ then weight of one mole of $X$ is ........... $\mathrm{g}$

($\Delta _o =$ crystal field splitting energy in an octahedral field, $P =$ Electron pairing energy)

| List $I$ (molecules/ions) | List $II$ (No. of lone pairs of $e ^{-}$ on central atom) |
| $A$ $IF_7$ | $I$ Three |
| $B$ $ICl^{-}_4$ | $II$ One |
| $C$ $XeF_6$ | $III$ Two |
| $D$ $XeF_2$ | $IV$ Zero |
Choose the correct answer from the options given below:
$C{H_3} - C \equiv CH\xrightarrow[{(ii)\,\,NaB{H_4}}]{{(i)\,\,Hg{{(OAC)}_2}/{H_2}O}}\,(Q)$
Choose the correct option