MCQ
The critical angle for total internal reflection of light going from medium $I$ to medium $II$ is given by the relation tan $i_C=\frac {5}{9}$ . The refractive index of the medium $I$ with respect to the medium $II$ is
  • A
    $1.8$
  • B
    $1.6$
  • C
    $\frac {\sqrt {156}}{5}$
  • $\frac {\sqrt {106}}{5}$

Answer

Correct option: D.
$\frac {\sqrt {106}}{5}$
d
$\tan c=\frac{5}{9}$

$\sin c=\frac{1}{\mu}=\frac{5}{\sqrt{106}}$

$\mu=\frac{\sqrt{106}}{5}$

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