MCQ
The current in the circuit shown in the figure considering ideal diode is
- A200A
- B$2 \times 10^{-4} A$
- C20A
- D$2 \times 10^{-3} A$
✓
Answer
(d) $2 \times 10^{-3} A$
Explanation: $I=\frac{(3.2-3) V }{100 \Omega}=2 \times 10^{-3} A$
Explanation: $I=\frac{(3.2-3) V }{100 \Omega}=2 \times 10^{-3} A$
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