The deviation of bond angle in cyclopropane: - Vidyadip

MCQ

The deviation of bond angle in cyclopropane:

A
49°.5′
B
24°.44′
C
−5°.16′
D
−9°.33′

✓

Answer

49°.5′

Explanation:

Deviation of the bond angle in cyclopropane is 109.5 - 60 = 49.5.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Hydrocarbons→Hydrocarbons — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

$s{p^3}$ hybridisation is found in

In the formation of $NaCl$ from $Na$ and $Cl$

In an isochoric process the increase in internal energy is

For an aqueous solution, the characteristic species of acid is

According to Kirchoff equation which of the following factor effect the enthalpy of reaction:

$C{{H}_{3}}-C\equiv C-C{{H}_{3}}\xrightarrow{Cold\,\,KMn{{O}_{4}}}(A)$

Product $(A)$ is

The free energy change for the following reactions are given below,${C_2}{H_2}(g) + \frac{5}{2}{O_2}(g)\, \to $$2C{O_2}(g) + {H_2}O(l);\,\Delta {G^o} = - 1234\,kJ$ $C(s) + {O_2}(g)\, \to C{O_2}(g)\,\,\Delta {G^o} = - 394\,kJ$${H_2}(g) + \frac{1}{2}{O_2}(g)\, \to \,{H_2}O(l)\,\,\,\Delta {G^o} = - 237\,kJ$

What is the standard free energy change for the reaction ${H_2}(g) + 2\,C\,(s) \to {C_2}{H_2}(g)$ .....$kJ$

If $IUPAC $ name of an element is $"unununium"$ then correct statement regarding element is

The oxidation state of Cr in CrO₅, is:

Below are two statements, one labeled as Assertion $(A)$ and the other as Reason $(R):$

Assertion $(A)$: Among group $13$ elements, boron's melting point is unusually high $(2453 \mathrm{~K})$.

Reason $(R):$ Solid boron has a strong crystalline lattice.

In the context of the above statements, choose the correct answer from the following options: