$2C_6H_6 (l) + 15O_2 (g) \longrightarrow 12CO_2 (g) + 6H_2O(l)$
at $300\, K$ is ....$J\,mol^{-1}$ ($R = 8.314\, J\, mol^{-1}\, K^{-1}$)
For the reaction $\Delta {n_g} = 12 - 15 = - 3$
$\Delta H - \Delta U = - 3 \times 8.314 \times 300$
$ = - 7482\,J\,mo{l^{ - 1}}$
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Assertion $A:$ A mixture contains benzoic acid and napthalene. The pure benzoic acid can be separated out by the use of benzene.
Reason $R:$ Benzoic acid is soluble in hot water.
In the light of the above statements, choose the most appropriate answer from the options given below.
$Cl_2 + 2Br^ - (aq.) \to 2Cl^-(aq.) + Br_2$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with