If $x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \mathrm{m}$ represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are
A$5 \mathrm{~m}, 2 \mathrm{~s}$
B$5 \mathrm{~cm}, 1 \mathrm{~s}$
C$5 \mathrm{~m}, 1 \mathrm{~s}$
D$5 \mathrm{~cm}, 2 \mathrm{~s}$
NEET 2024, Medium
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A$5 \mathrm{~m}, 2 \mathrm{~s}$
a $x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \mathrm{m}$
Amplitude $=5 \mathrm{~m}$
$\omega=\pi=\frac{2 \pi}{T}$
$T=\frac{2 \pi}{\pi}=2 \mathrm{~s}$
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