The displacements of two particles executing $S.H.M.$ on the same line are given. as $y_1=a \sin \left(\frac{\pi}{2} t+\phi\right)$ and $y_2=b \sin \left(\frac{2 \pi}{3} t+\phi\right)$. The phase difference between them at $t=1 \,s$ is .........
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(d)
Phase difference between them is just difference in the angular values.
Phase difference $\left.=\left(\frac{2 \pi}{3}+\phi\right)-\left(\frac{\pi}{2}+\phi\right)=\frac{\pi}{6}\right)$
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