MCQ
The equation $2{\cos ^{ - 1}}x + {\sin ^{ - 1}}x = \frac{{11\pi }}{6}$ has
- ✓No solution
- BOnly one solution
- CTwo solutions
- DThree solutions
==> ${\cos ^{ - 1}}x + ({\cos ^{ - 1}}x + {\sin ^{ - 1}}x) = \frac{{11\pi }}{6}$
==> ${\cos ^{ - 1}}x + \frac{\pi }{2} = \frac{{11\pi }}{6}$
$ \Rightarrow {\cos ^{ - 1}}x = 4\pi /3$
which is not possible as ${\cos ^{ - 1}}x \in [0,\,\pi ]$.
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$f(x) = sin^{-1} \left( {\frac{{\,\,1 - \,\,\left| x \right|}}{3}} \right) + cos^{-1}\left( {\frac{{\left| x \right|\,\, - \,\,3}}{5}} \right)$ .
Then domain of $f(x)$ is given by :