MCQ
The equation of the circle whose centre is $(-2,5)$ and radius 3 will be
  • A
    $x^2+y^2+4 x+10 y+20=0$
  • $x^2+y^2+4 x-10 y+20=0$
  • C
    $x^2+y^2+4 x+10 y-20=0$
  • D
    $x^2+y^2-4 x-10 y+20=0$

Answer

Correct option: B.
$x^2+y^2+4 x-10 y+20=0$
(B) $x^2+y^2+4 x-10 y+20=0$
Explanation :The equation of circle whose centre is $(-2,5)$ and radius is 3 , is given by
$\begin{array}{l}(x+2)^2+(y-5)^2=3^2 \\ \Rightarrow\left(x^2+4 x+4\right)+\left(y^2-10 y+25\right)=9 \\ \Rightarrow x^2+y^2+4 x-10 y+29-9=0 \\ \Rightarrow x^2+y^2+4 x-10 y+20=0\end{array}$

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