MCQ
The equivalent resistance and potential difference between $A$ and $B$ for the circuit is respectively
  • $4  \,\Omega$, $8\, V$
  • B
    $8 \,\Omega, \,\,4\, V$
  • C
    $2  \,\Omega$, $2\, V$
  • D
    $16  \,\Omega$, $8\, V$

Answer

Correct option: A.
$4  \,\Omega$, $8\, V$
a
The equivalent resistance between $C$ and $D$ is

$\frac{1}{{R'}} = \frac{1}{6} + \frac{1}{6} + \frac{1}{3} = \frac{2}{3}$ or $R' = \frac{3}{2} = 1.5\,\Omega $

Now the equivalent resistance between $A$ and $B$ as $R' = 1.5\,\Omega $ and $2.5\,\Omega $ are connected in series, so

Now by ohm's law, potential difference between $A$ and $B$ is given by ${V_A} - {V_B} = iR = 2 \times 4.0 = 8\,\,volt$

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