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In the adjoining circuit, the battery $E_1$ has an $e.m.f.$ of $12\, volts$ and zero internal resistance, while the battery $E_2$ has an $e.m.f.$ of $2\, volts$. If the galvanometer $G$ reads zero, then the value of the resistance $X$ in $ohms$ is
The resistance of the filament of an electric bulb changes with temperature. If an electric bulb rated $220\, volt$ and $100\, watt$ is connected $(220 \times 0.8)$ $volt$ sources, then the actual power would be
$n$ identical cells are joined in series with two cells $A$ and $B$ with reversed polarities. $emf$ of each cell is $E$ and internal resistance is $r$. Potential difference across cell $A$ and $B$ is : $(n > 4)$
Two bulbs consume same power when operated at $200\, V$ and $300\, V$ respectively. When these bulbs are connected in series across a $D.C$. source of $500\, V$, then