MCQ
The figure represents a voltage regulator circuit using a Zener diode. The breakdown voltage of the Zener diode is $6\,V$ and the load resistance is $R_L= 4\,k\Omega .$ The series resistance of the circuit is $R_i = 1\,k\Omega .$ If the battery voltage $V_B$ varies from $8\,V$ to $16\,V,$ what are the minimum and maximum values of the current through Zener diode?
  • A
    $0.5\,mA;\,\,0.6\,mA$
  • B
    $1\,mA;\,\,8.5\,mA$
  • C
    $1.5\,mA;\,\,8.5\,mA$
  • $0.5\,mA;\,\,8.5\,mA$

Answer

Correct option: D.
$0.5\,mA;\,\,8.5\,mA$
d
${{\text{V}}_{{\text{breaddwon }}}} = 6{\text{V}},$ ${{\text{R}}_{\text{L}}} = 4\,{\text{k}}\Omega ,$ ${{\text{R}}_{\text{i}}} = 1{\text{k}}\Omega $

${{\text{i}}_{\text{L}}} = \frac{6}{4} \times {10^{ - 3}} = $ $1.5 \times {10^{ - 3}} = 1.5{\text{mA}}$

$\mathrm{i}_{\mathrm{i}}=2 \times 10^{-3}$

${\text{i}} = {{\text{i}}_1} - {{\text{i}}_{\text{L}}} = 0.5{\text{mA}} - $ minimum current

$\mathrm{i}_{\mathrm{i}}=10 \times 10^{-3}=10 \mathrm{mA}$

$\operatorname{lmax}=8.5 \mathrm{mA}$

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