b Hint: There is hydrogen at first carbon (Anomeric $C$ ) for aldohexose whereas alkyl group for ketohexose.
Explanation
Since there are six carbons in the carbohydrate, it is a hexose. Also, there is hydrogen at anomeric carbon that is the first carbon.Anomeric $C$ is the new chiral center formed after cyclization.It is the cyclic form of D-glucose and as glucose has aldehyde functionality so it is the aldohexose.
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