MCQ
The formula of prussian blue is:
- A$ \mathrm{Na}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] $
- B$ \mathrm{Fe}(\mathrm{CN})_2 $
- C$ \mathrm{Fe}(\mathrm{CNS})_3 $
- ✓$ \mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 $
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$k =\left(6.5 \times 10^{12} \,s ^{-1}\right) e ^{-26000 K / T }$
is followed for the decomposition of compound $A$. The activation energy for the reaction is $.....\,kJ$ $mol ^{-1}$. [nearest integer]
(Given: $R =8.314 \,J\, K ^{-1}\, mol ^{-1}$ )
