MCQ
The hybridization of the central atom will change when
- A$NH_3$ combines with $H^+$
- B$H_3BO_3$ combines with $OH^-$
- C$NH_3$ forms $NH_2^-$
- D$H_2O$ combines with $H^+$
$\underset{s{{p}^{3}}}{\mathop{2N{{H}_{3}}}}\,\rightleftarrows \underset{s{{p}^{3}}}{\mathop{NH_{2}^{-}}}\,+\underset{s{{p}^{3}}}{\mathop{NH_{4}^{+}}}\,$
$\underset{s{{p}^{2}}}{\mathop{{{H}_{3}}B{{O}_{3}}}}\,+O{{H}^{-}}\to \underset{s{{p}^{3}}}{\mathop{{{[B{{(OH)}_{4}}]}^{-}}}}\,$
$\underset{s{{p}^{3}}}{\mathop{{{H}_{2}}O}}\,+{{H}^{+}}\rightleftarrows \underset{s{{p}^{3}}}{\mathop{{{H}_{3}}{{O}^{+}}}}\,$
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The equilibrium constant of the reaction $2N{H_3} + \frac{5}{2}{O_2} \rightleftharpoons 2NO + 3{H_2}O$ in terms of $K_1, K_2$ and $K_3$ is