MCQ
The hydrocarbon which can react with sodium in liquid ammonia is
- A$CH_3CH_2CH_2C \equiv CCH_2CH_2CH_3$
- ✓$CH_3CH_2C \equiv CH$
- C$CH_3CH \equiv CHCH_3$
- D$CH_3CH_2C \equiv CCH_2CH_3$
Hence $C H_{3} C H_{2} C \equiv C H$ is the correct option.
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Assertion $(A) :$ $I - Cl$ is more reactive than $I _{2}$.
Reason $(R):$ $I - Cl$ bond is weaker than $I-I$ bond.
In the light of the above statements, choose the most appropriate answer from the options given below:
$Cu^+ /Cu = + 0.52\, V$,
$Fe^{3+} /Fe^{2+} = +0.7 7\, V$,
$\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, = + 0.54\,V,$
$Ag^+ /Ag = + 0.88\,V$.
Based on the above potentials, strongest oxidizing agent will be