MCQ
The hydrocarbon which can react with sodium in liquid ammonia is
- A$CH_3CH_2CH_2C \equiv CCH_2CH_2CH_3$
- ✓$CH_3CH_2C \equiv CH$
- C$CH_3CH \equiv CHCH_3$
- D$CH_3CH_2C \equiv CCH_2CH_3$
Hence $C H_{3} C H_{2} C \equiv C H$ is the correct option.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
|
Exp. |
$[A]_0$ |
$[B]_0$ |
Rate (mole $s^{-1}$) |
|
$(1)$ |
$0.50$ |
$0.50$ |
$1.6 \times {10^{ - 4}}$ |
|
$(2)$ |
$0.50$ |
$1.00$ |
$3.2 \times {10^{ - 4}}$ |
|
$(3)$ |
$1.00$ |
$1.00$ |
$3.2 \times {10^4}$ |