MCQ
The IUPAC name for CH3CH(OH)CH2C(CH3)2OH is:
- A1, 1-dimethyl-1, 3-butanediol
- B2-methyl-2, 4 pentanediol
- C4-methyl-2 4-pentanediol
- D1, 3, 3- trimethyl 1-1, 3-propanediol
Explanation:
The compound has 2 alcohol groups at C-2 positions on both the sides. From this point we can not say from where to start numbering.
But if we number from right hand side there is also a methyl group at C-2 position. So we start number from right hand side.
Since there are two alcoholic group, we use suffix "diol".
Thus IUPAC name is: 2-Methyl-2,4 pentanediol.
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Product $(A)$ and $(B)$ is differentiated by
| Column $I$ | Column $II$ |
| $(A) \,XX '$ | $(i)$ $T-$shape |
| $(B)\,XX'_3$ | $(ii)$ Pentagonal bipyramidal |
| $(C)\,XX '_5$ | $(iii)$ Linear |
| $(D)\,XX '_7$ | $(iv)$ Square pyramidal |
| $(v)$ Tetrahedral |
$Cl_2(aq) + H_2S(aq) \to S(s) + 2H^+(aq) + 2Cl^-(aq)$ rate law is $r = K[Cl_2][H_2S]$
then which of these mechanism is/are consistent with this rate law
$(A)\, H_2S \rightleftharpoons H^+ + HS^-$ (fast)
$Cl_2 + HS^-\to 2Cl^-+ H^+ + S$ (slow)
$(B)\, Cl_2 + H_2S \to H^+ + Cl^-+ Cl^+ + HS^-$ (slow)
$Cl^+ + HS^-\to H^+ + Cl^-+ S$ (fast)