Download App

Hydrocarbons — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistryHydrocarbons1 Mark
MCQ
The IUPAC name of $\text{CH}_2=\text{C}-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$ is:
  • A
    2-methylbutene.
  • B
    1-methylpropene.
  • C
    2-methylbut-2-ene.
  • D
    2-methylprop-1-ene.
✓

Answer

  1. 2-methylprop-1-ene.

Explanation:

$\stackrel{{1\ \ \ }}{\hbox{CH}}_2=\stackrel{{2}}{\hbox{C}}-\stackrel{{3\ \ \ }}{\hbox{CH}}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \ \ \ \ \ _{2-\text{methylprop-1-ene}}$​​​​​​​

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Hydrocarbons→Hydrocarbons — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

In the reaction, $A + B$ $\rightleftharpoons$ $2C$, at equilibrium, the concentration of $A$ and $B$ is $0.20\,\,mol\,\,{l^{ - 1}}$ each and that of $C$ was found to be $0.60\,\,mol\,\,{l^{ - 1}}$. The equilibrium constant of the reaction is
→
The ratio of velocity of electron in second orbit of $He^+$ to third orbit of $B^{+4}$ is
→
The paramagnetic property of the oxygen molecule due to the presence of unpaired electorns present in
→
The colour of bromine solution is:
→
An electric discharge is passed through a mixture containing $50\, c.c$. of ${O_2}$ and $50 \,c.c.$ of ${H_2}$. The volume of the gases formed $(i)$ at room temperature and $(ii)$ at $110\,^o C$ will be
→
Which of the following is not correct
→
Oxidation number of S in S2​O3​2− is:
→
The enthalpy of formation of ethane $\left(\mathrm{C}_2 \mathrm{H}_6\right)$ from ethylene by addition of hydrogen where the bondenergies of $\mathrm{C}-\mathrm{H}, \mathrm{C}-\mathrm{C}, \mathrm{H}-\mathrm{H}$ are $414 \mathrm{~kJ}, 347 \mathrm{~kJ}$, $615 \mathrm{~kJ}$ and $435 \mathrm{~kJ}$ respectively is -. . . . . . . . .$\mathrm{kJ}$.
→
Which is the correct order of electronegativities
→
Which of the following compounds has a negative enthalpy of solution?
→