MCQ
The IUPAC name of [Ni(CO)4] is:
- ATetracarbonyl nickelete (0)
- BTetracarbonyl nickelete (II)
- CTetracarbonyl nickel (0)
- DTetracarbonyl nickel (II)
Explanation:
The IUPAC name of Ni(CO)4 is Tetracarbonyl nickel (0) since the oxidation state of carbonyl ligand is 0, so Ni will also be 0 and four ligand are bonded to central metal atom.
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Reason $(R)$: $\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{+}$complex ion has an octahedral geometry.
In the light of the above statements, choose the most appropriate answer from the options given below :