The kinetic energy of a particle executing $S.H.M.$ is $16\, J$ when it is at its mean position. If the mass of the particle is $0.32 \,kg$, then what is the maximum velocity of the particle ..... $m/s$
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(c) Kinetic energy at mean position, ${K_{\max }} = \frac{1}{2}mv_{\max }^2.$
$\Rightarrow {v_{\max }} = \sqrt {\frac{{2\,{K_{\max }}}}{m}} $ $ = \sqrt {\frac{{2 \times 16}}{{0.32}}} $
$ = \sqrt {100} $
$ = 10\,m/s.$
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