The lines ax + by + c = 0, where 3a + 2b + 4c = 0 are concurrent … - Vidyadip

MCQ

The lines $ax + by + c = 0$, where $3a + 2b + 4c = 0$ are concurrent at the point

A
$(1/2, 3/4)$
B
$(1, 3)$
C
$(3, 1)$
✓
$(3/4, 1/2)$

✓

Answer

Correct option: D.

$(3/4, 1/2)$

d
(d) Dividing both sides of relation $3a + 2b + 4c = 0$ by $4$, we get $\frac{3}{4}a + \frac{1}{2}b + c = 0$, which shows that for all values of $a, b$ and $c$ each member of the set of lines $ax + by + c = 0$ passes through the point $\left( {\frac{3}{4},\frac{1}{2}} \right)$.

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