- A$[Fe(C_2O_4)_3]^{3-}$
- ✓$[Fe(CN)_6]^{3-}$
- C$[Fe(CN)_6]^{4-}$
- D$[Fe(H_2O)_6]^{3+}$
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(Round off to the Nearest Integer).
[Given : Henry's law constant $= K _{ H }=8.0 \times 10^{4} kPa$ for $O _{2}$ Density of water with dissolved oxygen $=1.0\, kg\, dm ^{-3}$ ]

End product $(X)$ of the above reaction is
$(i)\, [Co(en)_2(Ox)]^+$
$(ii)\, [Fe(Trien)(Ox)]^+$
$(iii)\, [Ca(EDTA)]^{-2}$
$(iv)\, [Pt(Ox)_2 (H_2O)_2]$
$A$, (molecular formula $\left.\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}\right)$ with a straight chain structure gives a $C_{4}$ carboxylic acid. $A$ is :
$A \frac{{Li} {A} {H} {H}_{4}}{{H}_{3} {O}^{+}} \longrightarrow B \stackrel{\text { Oxidation }}{\longrightarrow} {C}_{4}-$ carboxylic acid
Choose the correct answer from the options given below: