Question
The optimal value of the objective function is attained at the points:

Answer

  1. Corner points of the feasible region
Solution:
Any point in the feasible region that gives the optimal value (maximum or minimum) of the objective function is called an optimal solution.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Evaluate $\begin{bmatrix}\text{x}^2&\text{x}^3&\text{x}^4\\\text{x}&\text{y}&\text{z}\\\text{x}^2&\text{x}^3&\text{x}^4\end{bmatrix}$ is:
If $\text{A}=\begin{bmatrix}1&0&0\\0&1&0\\\text{a}&\text{b}&-1\end{bmatrix},$ then $A^2$ is equal to:
Choose the correct answer from the given four options.The domain of the function $\cos^{-1}(2x - 1)$ is:
The equation of the curve aatisfying the differential $\text{y}(\text{x}+\text{y}^{3})\text{dx}=\text{x}(\text{y}^{3}-\text{x})$ dy and passing through the point (1, 1) is:
  1. $\text{y}^{3}-2\text{x}+3\text{x}^{2}\text{y}=0$
  2. $\text{y}^{3}+2\text{x}+3\text{x}^{2}\text{y}=0$
  3. $\text{y}^{3}+2\text{x}-3\text{x}^{2}\text{y}=0$
  4. None of these.
The function $\text{f(x)}=\sin^{-1}(\cos\text{x})$ is:
  1. Discontinuous at x = 0
  2. Continuous at x = 0
  3. Differentiable at x = 0
  4. None of these.
The sum of the order and the degree of the differential equation $\frac{d}{d x}\left(\frac{d y}{d x}\right)^3$ is
$\sin\Big\{2\cos^{-1}\Big(\frac{-3}{5}\Big)\Big\}$ is equal to:
  1. $\frac{6}{25}$
  2. $\frac{24}{25}$
  3. $\frac{4}{5}$
  4. $-\frac{24}{25}$
If the angle between the vectors $\overrightarrow{ a }$ and $\overrightarrow{ b }$ is $\frac{\pi}{4}$ and $|\vec{a} \times \vec{b}|=1$, then $\vec{a} \cdot \vec{b}$ is equal to
The vector component of $\vec{\text{b}}$ perpendicular to $\vec{\text{a}}$ is:
  1. $\big(\vec{\text{b}}.\vec{\text{c}}\big)\vec{\text{a}}$
  2. $\frac{\vec{\text{a}}\times\big(\vec{\text{b}}\times\vec{\text{a}}\big)}{|\vec{\text{a}}|^2}$
  3. $\vec{\text{a}}\times\big(\vec{\text{b}}\times\vec{\text{a}}\big)$
  4. None of these
The area bounded by the curve $x = 3y^2 – 9$ and the line $x = 0, y = 0$ and $y = 1$ is$:$