MCQ
The orbital angular momentum of $3p$ electron is
- A$\sqrt 3\ h$
- B$\sqrt 6\ h$
- Czero
- ✓$\sqrt 2 \frac{h}{{2\pi }}$
✓
Answer
Correct option: D.
$\sqrt 2 \frac{h}{{2\pi }}$
d
Orbital angular momentum $ = \sqrt {l(l + 1)} \frac{h}{{2\pi }}$ $l=1$ for $\mathrm{p}-$ orbital.
Orbital angular momentum $ = \sqrt {l(l + 1)} \frac{h}{{2\pi }}$ $l=1$ for $\mathrm{p}-$ orbital.
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